Math 509: Advanced Analysis
Homework 10
Lawrence Tyler Rush
<me@tylerlogic.com>
April 14, 2015
http://coursework.tylerlogic.com/courses/upenn/math509/homework10
1 Problem 22 from Vector Calculus Notes
2 Problem 23 from Vector Calculus Notes
3 Problem 24 from Vector Calculus Notes
According to the notes, an infinitesimal displacement has
| (3.1) |
which gives us a relationship between cartesian and spherical coordinates. Now we also know that
Differentiating each of these equations yields
dx | = sinθ cosφdr + r cosθ cosφdθ - r sinθ sinφdφ | |
|
dy | = sinθ sinφdr + r cosθ sinφdθ + r sinθ cosφdφ | |
|
dz | = cosθdr - r sinθdθ | | |
We can then plug these values into the left-hand side of equation 3.1 to obtain
dr + rdθ+ r sinθdφ | = (sinθ cosφdr + r cosθ cosφdθ - r sinθ sinφdφ)i+ | |
|
| (sinθ sinφdr + r cosθ sinφdθ + r sinθ cosφdφ)j+ | |
|
| (cosθdr - r sinθdθ)k | | |
Grouping the right-hand side by dr, rdθ, and r sinθdφ we then obtain
dr + rdθ+ r sinθdφ | = (sinθ cosφi + sinθ sinφj + cosθk)dr | |
|
| + (cosθ cosφi + cosθ sinφj - sinθk)rdθ | |
|
| + (cosφj - sinφi)r sinθdφ | | |
implying that
| = sinθ cosφi + sinθ sinφj + cosθk | |
|
| = cosθ cosφi + cosθ sinφj - sinθk | |
|
| = -sinφi + cosφj | | |
4 Problem 25 from Vector Calculus Notes
5 Problem 26 from Vector Calculus Notes
6 Problem 27 from Vector Calculus Notes
7 Problem 28 from Vector Calculus Notes
8 Problem 29 from Vector Calculus Notes