Math 509: Advanced Analysis

Homework 10
Lawrence Tyler Rush
<me@tylerlogic.com>
April 14, 2015
http://coursework.tylerlogic.com/courses/upenn/math509/homework10

1 Problem 22 from Vector Calculus Notes


2 Problem 23 from Vector Calculus Notes


3 Problem 24 from Vector Calculus Notes


According to the notes, an infinitesimal displacement has
dxi+ dyj+ dzk = dℓ = drˆr+ rdθˆθ+ rsin θdφˆφ
(3.1)

which gives us a relationship between cartesian and spherical coordinates. Now we also know that

x = rsin θcosφ     y = rsin θsin φ     z = rcosθ

Differentiating each of these equations yields

dx = sinθ cosφdr + r cosθ cosφdθ - r sinθ sinφdφ
dy = sinθ sinφdr + r cosθ sinφdθ + r sinθ cosφdφ
dz = cosθdr - r sinθdθ
We can then plug these values into the left-hand side of equation 3.1 to obtain
drˆr + rdθθˆ+ r sinθdφˆφ = (sinθ cosφdr + r cosθ cosφdθ - r sinθ sinφdφ)i+
  (sinθ sinφdr + r cosθ sinφdθ + r sinθ cosφdφ)j+
  (cosθdr - r sinθdθ)k
Grouping the right-hand side by dr, rdθ, and r sinθdφ we then obtain
drˆr + rdθˆθ+ r sinθdφˆφ = (sinθ cosφi + sinθ sinφj + cosθk)dr
   + (cosθ cosφi + cosθ sinφj - sinθk)rdθ
   + (cosφj - sinφi)r sinθdφ
implying that
ˆr = sinθ cosφi + sinθ sinφj + cosθk
ˆθ = cosθ cosφi + cosθ sinφj - sinθk
ˆφ = -sinφi + cosφj

4 Problem 25 from Vector Calculus Notes


5 Problem 26 from Vector Calculus Notes


6 Problem 27 from Vector Calculus Notes


7 Problem 28 from Vector Calculus Notes


8 Problem 29 from Vector Calculus Notes